(3x^2-2)(2x^4+x^2+4)=0

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Solution for (3x^2-2)(2x^4+x^2+4)=0 equation: 


Simplifying
(3x2 + -2)(2x4 + x2 + 4) = 0

Reorder the terms:
(-2 + 3x2)(2x4 + x2 + 4) = 0

Reorder the terms:
(-2 + 3x2)(4 + x2 + 2x4) = 0

Multiply (-2 + 3x2) * (4 + x2 + 2x4)
(-2(4 + x2 + 2x4) + 3x2 * (4 + x2 + 2x4)) = 0
((4 * -2 + x2 * -2 + 2x4 * -2) + 3x2 * (4 + x2 + 2x4)) = 0
((-8 + -2x2 + -4x4) + 3x2 * (4 + x2 + 2x4)) = 0
(-8 + -2x2 + -4x4 + (4 * 3x2 + x2 * 3x2 + 2x4 * 3x2)) = 0
(-8 + -2x2 + -4x4 + (12x2 + 3x4 + 6x6)) = 0

Reorder the terms:
(-8 + -2x2 + 12x2 + -4x4 + 3x4 + 6x6) = 0

Combine like terms: -2x2 + 12x2 = 10x2
(-8 + 10x2 + -4x4 + 3x4 + 6x6) = 0

Combine like terms: -4x4 + 3x4 = -1x4
(-8 + 10x2 + -1x4 + 6x6) = 0

Solving
-8 + 10x2 + -1x4 + 6x6 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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